2=-x^2-13x

Solution for 2=-x^2-13x equation:

2=-x^2-13x

We move all terms to the left:

2-(-x^2-13x)=0

We get rid of parentheses

x^2+13x+2=0

a = 1; b = 13; c = +2;
Δ = b2-4ac
Δ = 132-4·1·2
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{161}}{2*1}=\frac{-13-\sqrt{161}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{161}}{2*1}=\frac{-13+\sqrt{161}}{2}
$